ABC214-D: Sum of Maximum Weights 
問題 
解説 
辺を重み順にソートして, 小さい順に辺を張ることを考える. 与えられるグラフは木なので, 辺を張るとき2つの頂点は必ず非連結となっている.
辺の重みが小さい順に辺 
したがって, 辺の重みが小さい順に辺を張っていき Union Find Tree を使って連結成分のサイズを取得して答えを加算していけば良い.
実装例 
C++ 
cpp
#include <algorithm>
#include <iostream>
#include <vector>
struct UnionFind {
  std::vector<int> parent_or_size;
  int cnt;
  UnionFind(int n) : parent_or_size(n, -1), cnt(n) {}
  void unite(int x, int y) {
    x = find_root(x);
    y = find_root(y);
    if (x == y) {
      return;
    }
    if (-parent_or_size[x] < -parent_or_size[y]) {
      std::swap(x, y);
    }
    parent_or_size[x] += parent_or_size[y];
    parent_or_size[y] = x;
    cnt--;
  }
  bool is_same_root(int x, int y) { return find_root(x) == find_root(y); }
  int find_root(int x) {
    if (parent_or_size[x] < 0) {
      return x;
    }
    return parent_or_size[x] = find_root(parent_or_size[x]);
  }
  int size(int x) { return -parent_or_size[find_root(x)]; }
};
struct Edge {
  int u, v;
  long long w;
  Edge() {}
  Edge(int x, int y, long long z) : u(x), v(y), w(z) {}
};
bool comp(Edge &a, Edge &b) { return a.w < b.w; }
int main() {
  int N;
  std::cin >> N;
  std::vector<Edge> edges(N - 1);
  for (int i = 0; i < N - 1; i++) {
    int u, v, w;
    std::cin >> u >> v >> w;
    edges[i] = Edge(u - 1, v - 1, w);
  }
  std::sort(edges.begin(), edges.end(), comp);
  UnionFind uf_tree(N);
  long long ans = 0;
  for (int i = 0; i < N - 1; i++) {
    int u = edges[i].u;
    int v = edges[i].v;
    long long w = edges[i].w;
    ans += w * (long long)uf_tree.size(u) * (long long)uf_tree.size(v);
    uf_tree.unite(u, v);
  }
  std::cout << ans << "\n";
  return 0;
}Python 
python
#!/usr/bin/env python3
class UnionFind:
    def __init__(self, n):
        self.parent_or_size = [-1 for _ in range(n)]
        self.cnt = n
    def unite(self, x, y):
        x, y = self.find_root(x), self.find_root(y)
        if x == y:
            return
        if -self.parent_or_size[x] < -self.parent_or_size[y]:
            x, y = y, x
        self.parent_or_size[x] += self.parent_or_size[y]
        self.parent_or_size[y] = x
        self.cnt -= 1
    def is_same_root(self, x, y):
        return self.find_root(x) == self.find_root(y)
    def find_root(self, x):
        if self.parent_or_size[x] < 0:
            return x
        self.parent_or_size[x] = self.find_root(self.parent_or_size[x])
        return self.parent_or_size[x]
    def size(self, x):
        return -self.parent_or_size[self.find_root(x)]
N = int(input())
uvw = [[int(x) for x in input().split()] for _ in range(N - 1)]
uvw.sort(key=lambda x: x[2])
ans = 0
uf_tree = UnionFind(N)
for (u, v, w) in uvw:
    ans += w * uf_tree.size(u - 1) * uf_tree.size(v - 1)
    uf_tree.unite(u - 1, v - 1)
print(ans)